Question

What is the solution of log(2x + 6) 8 = 3

Answer 1

x = −2

x = 2

x = −3

x = 3

Answer 2

(2x+6)^3 = 8

hint: you can write 8 as 2^3

Answer 3

\[\Large \log_{b} A = C \quad means \quad A = b^C\]

Answer 4

is it -2?

Answer 5

Yes, x = -2

Answer 6

yay i tries solving it the way you guys all taught me :)

Answer 7

i need help with others

Answer 8

Post the questions and hopefully someone will be able to answer.

Answer 9

For the graphed function f(x) = (4)^(x - 1) + 2, calculate the average rate of change from x = 2 to x = 4.

Answer 10

is there a formula for this?

Answer 11

Average rate of change of f(x) over the interval [a, b] = { f(b) - f(a) } / (b - a)

Answer 12

soo.. how would i do that

Answer 13

ou are given f(x). Here the interval is [2, 4]. So a = 2, b = 4
Find f(4) by setting x = 4 in the function.
Find f(2) by setting x = 2 in the function.
Plug the numbers into the formula for average rate of change.

Answer 14

f(4)-f(a)/4-2?

Answer 15

{ f(4) - f(2) } / (4 - 2)

Answer 16

2**

Answer 17

so that would give me..

Answer 18

What are you getting?

Answer 19

-30?

Answer 20

68

Answer 21

Try again.

Answer 22

Is this the function? \[\Large f(x) = 4^{x-1} + 2\]

Answer 23

yes

Answer 24

f(4) = 4^(4-1) + 2 = 4^3 + 2 = 64 + 2 = 66

Answer 25

thats the solution? 66 wow thank you

Answer 26

thats it?

Answer 27

No 66 is not the solution. I just evaluated it at x = 4.
You can evaluate it at x = 2 in a similar way.
Then find { f(4) - f(2) } / (4 - 2)

Answer 28

i see, i got 8.

Answer 29

and then 58/2...

Answer 30

f(4) = 4^(4-1) + 2 = 4^3 + 2 = 64 + 2 = 66
f(2) = 4^(2-1) + 2 = 4^1 + 2 = 6
Average rate of change of f(x) over the interval [2, 4] = { f(4) - f(2) } / (4 - 2) =
(66-6)/(4-2) = 60/2 = 30

Answer 31

ohh, wow i had 8... careless mistakes. this was really helpful :) thank you

Answer 32

you are welcome.