Question

Suppose you select a 3-digit number at random from the set of all positive 3-digit
numbers. Find each probability, number less than 900

Answer 1

all 3 digit numbers range from 100 to 999 (assuming you dont count 099 as a 3 digit)
so in total we have 899 numbers. 800 of them are less than 900.
The fraction we get is 800 / 899, as a percentage is 88.98776418% chance

Answer 2

800 positive numbers?

Answer 3

Ooo, good point. If you also include negative numbers, hmm. Then the number of 3 digit numbers becomes 899 x 2 = 1798
Assuming -999 is less than 900, then your chance is 1699 / 1798 = 94.5%
But I haven't seen it worded like that before

Answer 4

no negative numbers ,but how many positive numbers are in 3 digits that are less than 900?

Answer 5

To clarify my initial answer.
0-99 are not 3 digit numbers
100 - 899 are 3 digit numbers less than 900, which in total is 800 unique numbers.
The full range is 100 to 999 which is 899 unique digits. The fraction is 800 / 899

Answer 6

it isnt 100 minus 899 sorry. I meant 100 to 899. There are 800 positive numbers between them.
Does this answer your question?

Answer 7

oh sorry haha! I meant that too. Not the - sign

Answer 8

800 are positive?

Answer 9

Yes. 800 are positive.

Answer 10

Oh shoot! I think there are 900 3 digit numbers total, my bad. 100 to 999 gives you 900, forgot to include the 100.
But there are only 800 3 digit numbers below 900