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Geometry 12 Online
OpenStudy (anonymous):

find an equation of the circle shown below A. (x + 10)^2 + (y − 10)^2 = 289 B. (x − 10)^2 + (y − 10)^2 = 289 C. (x − 10)^2 + (y + 10)^2 = 289 D. (x − 10)^2 + (y − 10)^2 = 17 please help ! the picture is below

OpenStudy (anonymous):

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OpenStudy (mertsj):

1. Find the midpoint of the diameter. That is the center 2. Find the distance from the center to one of the points. That is the radius. 3. Plug the center and radius into: (x-h)^2+(y-k)^2=4^2

OpenStudy (anonymous):

For Mertsj 3) The equation of a circle is (x-h)^2 + (y-k)^2 = r^2 where r is the radius of the circle, k is the shift on the y axis, and, h is the shift on the x axis.

OpenStudy (anonymous):

Find the radius by using the distance formula. (x2 - x1)^2 + (y2-y1)^2 = d^2. d will be your diameter. Divide it by 2 for the radius.

OpenStudy (anonymous):

So that is the concept behind it, but you can find the answer with just one method. Do you recall what a quadrant is?

OpenStudy (anonymous):

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OpenStudy (anonymous):

You simply need to see where your midpoint lies in the graph I drew.

OpenStudy (anonymous):

wait for y I got 10

OpenStudy (anonymous):

ohh I see what I did wrong you're right. but what do you do after you find the midpoint ?

OpenStudy (anonymous):

Recall (x-h)^2 + (y-k)^2 = r^2 This is giving h and k.

OpenStudy (anonymous):

Oh...I'm going to delete a mistake.

OpenStudy (anonymous):

You're right about y being 10. So is x.

OpenStudy (anonymous):

Because it's actually the avg of the 2 points. So for x it is (2+18)/2 = 10 and for y it is (25+(-5))/2 = 10. Sorry about that...

OpenStudy (anonymous):

And (h,k) is your center, Your center is (10,10).

OpenStudy (anonymous):

So your answer is B. (x − 10)^2 + (y − 10)^2 = 289

OpenStudy (anonymous):

Again, sorry for the confusion earlier. Let me know if you need additional help

OpenStudy (anonymous):

its alright lol, I actually understand it surprisingly lol thank you for the help :)

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