Question

q

Answer 1

q attached below .

Answer 2

any body help !

Answer 3

Phi and R look easy to determine! pythagorean theorem and right angle triangle trigononmetry.

Answer 4

@CGGURUMANJUNATH

Answer 5

phi and r are ok,i know we can use pythagorus theorem ,but how to find r',theta ' and phi ' ? @ganeshie8

Answer 6

ok

Answer 7

phi can be calculated by taking velocity vertical component, and for theta just consider the horizontal component,

Answer 8

and try to imagine these 3D questions in front of your eyes

Answer 9

and is this a ques of ML khanna?

Answer 10

can u show ur steps plz @divu.mkr ?

Answer 11

i'd say that its just basic imagination...

Answer 12

steps !

Answer 13

okkk. :D

Answer 14

wasn't that enuf with hints..?
i prefer not to give solutions...

Answer 15

can u draw figure ?

Answer 16

isnt the figure present in the ques?

Answer 17

do u know or not ?

Answer 18

i don't need final answer

Answer 19

i do...and i know

Answer 20

@robtobey

Answer 21

omega=v(perp)/R
and omega = d(theta)/dt

Answer 22

any idea what am i saying?
its a bit of physics here..

Answer 23

\(\dot{R}\) is simply the component of \(\vec{v}\) along OB

Answer 24

start by finding the components of \(\vec{v}\) along y and z axis

Answer 25

along y==>300sin theta
x==>300cos theta

Answer 26

is it right @ganeshie8 ?

Answer 27

Noo..
300 is height, its not velocity

Answer 28

\(\vec{v} = 400~ km/h\) along AB

Answer 29

we need to find \(\angle A\) first

\(\large \tan \angle A = \frac{1}{2}\)

Answer 30

ok

Answer 31

find angle A in degrees

Answer 32

once we have A,
z-component of speed = \(400\sin A\)
y-component of speed = \(400\cos A\)

find these two first

Answer 33

ok

Answer 34

a=26.56

Answer 35

<A

Answer 36

<A=26.56 DEGREES

Answer 37

178-Z
357-Y

Answer 38

Z COMPONENT OF SPEED=178
Y COMPONENT OF SPEED=357

Answer 39

OK

Answer 40

yah, so we have z component of speed.
we can find the component of speed along OB, \(\dot{R}\)