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Mathematics 8 Online
OpenStudy (anonymous):

Define as Max or MIn

OpenStudy (anonymous):

I found e^a-1 to be critical point

OpenStudy (anonymous):

but how do i tell if it its min or max?

OpenStudy (anonymous):

Generally you can take the second derivative, or you can test the 1st derivative at a point on either side of it. For instance if you found from the left it makes the derivative neg but on the right it is positive, that would be a max and vise versa would be a min.

OpenStudy (anonymous):

Sorry I reversed max and min. positive -> negative would be max where the highest point is your answer.

OpenStudy (anonymous):

Can you type out the problem? I need to work on these as well.

OpenStudy (anonymous):

okay, for the 1st derivative test would i make it -e^a-1 and 2e^a-1?

OpenStudy (anonymous):

I'm not sure how a is part of your function. Is it an inverse trig func?

OpenStudy (anonymous):

f(x)=ax-xlnx

OpenStudy (anonymous):

the derivative is a-lnx-1

OpenStudy (anonymous):

a is just a constant

OpenStudy (anonymous):

Hmm, so the f"(x)=-1/x. I am going through right now, but at y=0 there is a nasty little asymptote that I am trying to figure out.

OpenStudy (phi):

but you eval f'' at x= e^(a-1)

OpenStudy (phi):

e^(a-1) is always positive, so f'' at your critical pt -1/e^(a-1) is negative.

OpenStudy (anonymous):

okay so its a maximum

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