MEDAL WILL BE AWARDED. Please help. See attachment
@amistre64 @hartnn @ranga @AkashdeepDeb
Step #1 - Name Stuff. Q1 - Name What? A1 - What does it want? Name that. G = Price of a stick of gum Start traslating the problem statement.
Let \(x\) be the quantity of gum purchased, and \(y\) be the price of one piece. You have the system, \[\begin{cases}xy=2.16\\ (x+3)(y-1)=2.16\end{cases}\] Solve for \(x\).
How do I solve for x?
Substitution should work. From the first equation, you have \(y=\dfrac{2.16}{x}\). Expanding the second equation, you have \[xy+3y-x-3=2.16\] Plug in the expression for \(y\): \[x\left(\frac{2.16}{x}\right)+3\left(\frac{2.16}{x}\right)-x-3=2.16\\ 2.16+\frac{6.48}{x}-x-3=2.16\\ 0=x+3-\frac{6.48}{x}\]
Is there any easier way than that please? I am not up to that level yet :)
It's a quadratic in disguise. Have you worked with quadratic equations? Multiply both sides by \(x\): \[0=x^2+3x-6.48\]
No
So you've never seen this formula before? \[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
no
Are you allowed to plot graphs and see where they intersect and find the solution that way?
well i dont know. i mean is there anything easier than a quadratic equation or something?
The $2.16 may have to be converted to pennies in the equations.
so that would be 216 pennies right?
Yes. You can write various factors of 216 and create a table and from there you may be able to find the answer.
any easier way than that?
Try out each answer choice. And you can eliminate the ones that don't work.
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