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Mathematics 7 Online
OpenStudy (anonymous):

Is my answer right again ?

OpenStudy (anonymous):

OpenStudy (anonymous):

NOpe

OpenStudy (anonymous):

Can you tell me the formula ?

OpenStudy (anonymous):

(9 choose 3)

OpenStudy (mertsj):

You forgot that the order doesn't make any difference.

OpenStudy (anonymous):

the answer is 27

OpenStudy (anonymous):

because 9 times 3=27

OpenStudy (mertsj):

The answer is NOT 27

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

if it's not 27, then it must be 3

OpenStudy (anonymous):

(9 - 3)! / 9!

jimthompson5910 (jim_thompson5910):

There are 3! = 3*2*1 = 6 ways to choose 3 items from a total set of 3 (assuming order matters) So because overall order doesn't matter, this means that there are 6 different copies of the same combos. So essentially you are over-counting by a factor of 6. To correct this, you have to divide by 6.

OpenStudy (mertsj):

You have 9 choices for the first veggie, 8 for the second veggie, and 7 for the third veggie. That is 9 x 8 7 which is 504. BUT there are 3! arrangements of your three choices so divide that answer by 3! or 6

OpenStudy (anonymous):

84

OpenStudy (mertsj):

Bingo

OpenStudy (anonymous):

Thank you, mertsj.

OpenStudy (anonymous):

combinations of n things taken r at a time = n!/r!(n-r)! 9*8*7/3*2*1=84

OpenStudy (mertsj):

yw

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