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OpenStudy (anonymous):
OpenStudy (anonymous):
NOpe
OpenStudy (anonymous):
Can you tell me the formula ?
OpenStudy (anonymous):
(9 choose 3)
OpenStudy (mertsj):
You forgot that the order doesn't make any difference.
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OpenStudy (anonymous):
the answer is 27
OpenStudy (anonymous):
because 9 times 3=27
OpenStudy (mertsj):
The answer is NOT 27
OpenStudy (anonymous):
why?
OpenStudy (anonymous):
if it's not 27, then it must be 3
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OpenStudy (anonymous):
(9 - 3)! / 9!
jimthompson5910 (jim_thompson5910):
There are 3! = 3*2*1 = 6 ways to choose 3 items from a total set of 3 (assuming order matters)
So because overall order doesn't matter, this means that there are 6 different copies of the same combos. So essentially you are over-counting by a factor of 6. To correct this, you have to divide by 6.
OpenStudy (mertsj):
You have 9 choices for the first veggie, 8 for the second veggie, and 7 for the third veggie. That is 9 x 8 7 which is 504. BUT there are 3! arrangements of your three choices so divide that answer by 3! or 6
OpenStudy (anonymous):
84
OpenStudy (mertsj):
Bingo
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OpenStudy (anonymous):
Thank you, mertsj.
OpenStudy (anonymous):
combinations of n things taken r at a time = n!/r!(n-r)!
9*8*7/3*2*1=84