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Mathematics 7 Online
OpenStudy (anonymous):

Some Log help needed

OpenStudy (anonymous):

What's the problem?

OpenStudy (anonymous):

OpenStudy (anonymous):

x+3 = ln(.9). .2x = ln(t). Remember, the log in whatever base (in this case, e) will always negate the base that is raised to a power.

OpenStudy (anonymous):

And vice versa as well.

OpenStudy (anonymous):

wait you lost me

OpenStudy (anonymous):

Where did I lose you? e^x is e to the power of x. If you want to get x just by itself - if x is in the power - then you can take the natural log (ln) of e^x, which gets rid of the e, just giving you x.

OpenStudy (anonymous):

Got it got it

OpenStudy (anonymous):

what about \[e \ln \sqrt{13}\]

OpenStudy (anonymous):

So... What are you trying to do in this one?

OpenStudy (anonymous):

Just evaluating the expression

OpenStudy (anonymous):

@DorianGray ?

OpenStudy (anonymous):

Um. Take the ln of root 13, then multiply by e.

OpenStudy (anonymous):

Got it

OpenStudy (anonymous):

Cool cool.

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