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Some Log help needed
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What's the problem?
x+3 = ln(.9). .2x = ln(t). Remember, the log in whatever base (in this case, e) will always negate the base that is raised to a power.
And vice versa as well.
wait you lost me
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Where did I lose you? e^x is e to the power of x. If you want to get x just by itself - if x is in the power - then you can take the natural log (ln) of e^x, which gets rid of the e, just giving you x.
Got it got it
what about \[e \ln \sqrt{13}\]
So... What are you trying to do in this one?
Just evaluating the expression
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@DorianGray ?
Um. Take the ln of root 13, then multiply by e.
Got it
Cool cool.
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