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Mathematics 19 Online
OpenStudy (anonymous):

help plz

OpenStudy (anonymous):

sara places a ladder on level ground against a vertical wall.when the base of the ladder is 20ft from the wall,the ladder reaches a height of 15ft along the wall.sara then moves the base 7ft closer to the wall. to the nearset foot,how high up the wall does the ladder now reach

OpenStudy (anonymous):

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OpenStudy (anonymous):

had that part already so im in right direction

OpenStudy (anonymous):

find the height of the ladder via pythagoras as \(\sqrt{20^2+15^2}=25\) or by remembering the mother of all right triangles 3 - 4 - 5, making this one 15 - 10 - 25

OpenStudy (anonymous):

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OpenStudy (anonymous):

im taking trig if that helps

OpenStudy (anonymous):

the height of the ladder is now again given by pythagoras as \[\sqrt{25^2-13^3}\]whatever that is

OpenStudy (anonymous):

trig or whatever, this is all about right triangles, as is much of trig

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