Question

CAN SOMEONE EXPLAIN TO ME HOW DO THIS ?? My teacher didn't really explain..
_Co(g) + O2(g) --> Co2(g)

Answer 1

first you have to balance it
2CO + O2 = 2CO2
/2CO(g) / + O2(g) /= CO2(g)
so you have a 2:1:1 ratio
you know the formula n=m/M moles=mass/molar mass
well use this later

/2CO(g) / + O2(g) /= CO2(g)
mass /3.90g / 3.45g / x

we call this x because we are trying to determine the maximum mass of CO2 that can form

CO is the limiting reactant so we will use O2 to determine the mass of CO2

back to n=m/M
for O2 it is n=3.45g/32g/mol
32 is the Molar mass
n=0.1078125 moles of O2

there is a 1:1 ratio of O2:CO2
so there are also 0.1078125 moles of CO2

so using n=m/M for CO2 we can plug in the n and also M (32+12)
0.1078125=m/44
m=4.74grams

SO the max amount of CO2 that could form is 4.74 grams.
http://answers.yahoo.com/question/index?qid=20110119190039AAFjyS5

Answer 2

that confused me.. hah