Question

If the die is tossed twice, find the probability that the sum of the numbers appearing is at least 6

Answer 1

total outcome=6*6=36 i.e <1,1><1,2><1,3>.......<6,4><6,5><6.6>
Now no of outcome with sum at least 6 = 36- no of outcomes having sum less than 6

Outcomes having sum less than 6 = {1,1}, {1,2}, {1,3}, {1,4}, {2,1}, {2,2},{2,3}, {3,1}, {3,2}, {4,1}

no of outcome having sum less than 6=10
no of outcome having sum atleast 6 i.e favourable outcome= 36-10=26

probability= no. of favourable outcome/ total no of outcome
= 26/36
=13/18

Answer 2

Thank you (Mike, Clifton Park, N.Y.)