Question

Eliminate the parameter.
x = t - 3, y = t2 + 5

Answer 1

in the first equation solve for t, then replace it into the second equation.

Answer 2

y = x2 + 14?

Answer 3

NO. from the first equation
\[\large t=x+3 \]
so
\[\large y=t^2+5=(x+3)^2+5 \]

Answer 4

This has to be it: y = x2 + 6x + 14

Answer 5

yes. but there's (usually) no need to expand the square: u lose information.

Answer 6

(i mean u hide it, u don't lose it, it is still there)