Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Prove: (cos^2)θ=((cot^2)θ)/(1+(cot^2)θ)

OpenStudy (solomonzelman):

@Owen17, good?

OpenStudy (solomonzelman):

\[Cos^2x=\frac{Cot^2x}{1+Cot^2x}\]\[Cos^2x=\frac{Cot^2x}{Csc^2x}\]\[Cos^2x=\frac{Cos^2x/Sin^2x}{1/Sin^2x}\]\[Cos^2x=\frac{Cos^2x}{1}\]\[Cos^2x=Cos^2x\]

OpenStudy (solomonzelman):

Identities used: \[Cot^2x+1=Csc^2x\]\[Cot^2x=Cos^2x/Sin^2x\]\[Csc^2x=1/Sin^2x\]\[\frac{a}{b} \div \frac{c}{d} =\frac{a}{b} \times \frac{d}{c}\]

OpenStudy (anonymous):

Perfect, thank you very much for your help.

OpenStudy (solomonzelman):

Anytime!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!