Question

what are the first five terms in the geometric sequence

Answer 1

(continued) when given an= (2)^n-1 and starting with n=1

Answer 2

2^1-1
2^2-1
2^3-1
2^4-1
2^5-1

Answer 3

I'm still confused? How can I use what you've given me to find the sequence?

Answer 4

i listed the first five terms in the sequence. to find term a[n], use the given formula
a[n]= (2)^n-1

Answer 5

So if I'm understanding then the sequence would be 2, 4, 6, 8, 10?

Answer 6

not quite. the sequence 2^n is 2, 4, 8, 16, 32, 64, etc.
the sequence 2^n-1 would then be 1, 3, 7, 15, 31, 63, etc.

Answer 7

So here are the answers available: {2, 4, 8, 16, 64}, {1, 2, 4, 8, 16}, {1, 2, 4, 6, 8}, and {2, 4, 6, 8, 10}. So I'm guessing the best answer is the first sequence even though there is no 32?

Answer 8

actually, the sequence must be (2)^(n-1) and not ((2)^n)-1. misread it.
in which case, the answer would be the second sequence

Answer 9

2^(n-1)
n=1: 2^(1-1) = 2^0 = 1
n=2: 2^(2-1) = 2^1 = 2
n=3: 2^(3-1) = 2^2 = 4
n=4: 2^(4-1) = 2^3 = 8
n=5: 2^(5-1) = 2^4 = 16

Answer 10

This is so not what I would have come up with but your explanation makes perfect sense and so much easier than what I was making it out to be. Thank you so much!!!

Answer 11

:)