Question

(6/x+1)+(9/2x+2)

Answer 1

Are x + 1 and 2x + 2 denominators?

Answer 2

yes

Answer 3

would you not multiply
(6/x+1) by 2/2 because
2x + 2 = 2(x+1)
?

Answer 4

That's not what you wrote.

You wrote:

\( (\dfrac{6}{x} + 1 ) + (\dfrac{9}{2} x + 2 ) \)

but I think you meant to write:

\( \left(\dfrac{6}{x + 1} \right) + \left(\dfrac{9}{2x + 2} \right) \)

Answer 5

or i am sorry . meant to write the second one you put

Answer 6

You have 2 denominators, x + 1 and 2x + 2.
2x + 2 factors into 2(x + 1).

Now look again at the denominators:
x + 1 and 2(x + 1)

The LCD is 2(x + 1)

By multiplying the first fraction by 2/2, you will have the same denominator, 2(x + 1),
in both fractions. Then you can add them.