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solve for all valid values of x
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this one requires one more step first \[\log(A)+\log(B)=\log(AB)\] so the first step is to write \[\log_{18}(x(x-1))=1\]
then convert to exponential form, and finally solve for \(x\) you will have to solve a quadratic equation do you know how to do that?
I don't think so
For that question, you need the log rules. You should know that logx+logy=logxy. So, you get \[\log_{18}(x(x-3))=\log_{18}(x²-3x)\] Now, if you remember how log works: \[\log_{a}(b)=c \] can be transfer in: \[a^c=b\] So, can you manage from now on?
6,3?
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For what grade is this? 12th?
-3
10th @tHe_FiZiCx99
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