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Mathematics 9 Online
OpenStudy (anonymous):

solve for all valid values of x

OpenStudy (anonymous):

this one requires one more step first \[\log(A)+\log(B)=\log(AB)\] so the first step is to write \[\log_{18}(x(x-1))=1\]

OpenStudy (anonymous):

then convert to exponential form, and finally solve for \(x\) you will have to solve a quadratic equation do you know how to do that?

OpenStudy (anonymous):

I don't think so

OpenStudy (anonymous):

For that question, you need the log rules. You should know that logx+logy=logxy. So, you get \[\log_{18}(x(x-3))=\log_{18}(x²-3x)\] Now, if you remember how log works: \[\log_{a}(b)=c \] can be transfer in: \[a^c=b\] So, can you manage from now on?

OpenStudy (anonymous):

6,3?

OpenStudy (the_fizicx99):

For what grade is this? 12th?

OpenStudy (anonymous):

-3

OpenStudy (anonymous):

10th @tHe_FiZiCx99

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