Question

integrals help!!

Answer 1

\[\int\limits\limits_{}^{?} (4x^2-4x+1)/x^3/2\]

Answer 2

Supposed to be like that?

Answer 3

ugh i dont know how to do this here

Answer 4

no its like

Answer 5

4x^2-4x+1 / x^3/2

Answer 6

compute each of the following integrals

Answer 7

u substitution

Answer 8

the integral has no high or low

Answer 9

Gotcha, to thepower of (3/2). Well, separateit into separate integrals. Every termin the numerator can be made into its own fraction divided by the denominator.

Answer 10

which one would be my U tho the 4x^2-4x+1?

Answer 11

no

Answer 12

(4x^2-4x+1)(x)^-3/2 like that

Answer 13

4x^2

Answer 14

\[\int\limits_{}^{}\frac{4x^{2}}{x^{3/2}}-\int\limits_{}^{}\frac{ 4x }{ x^{3/2} }+ \int\limits_{}^{}\frac{1}{x^{3/2}}\]

Answer 15

The first two integrals can be reduced by dividing the x's, the 3rd term is justintegrable straight away.

Answer 16

okay so just subtract them right?

Answer 17

Right. Subtract exponents when youdivide :)

Answer 18

so i will get

Answer 19

4x^1/2 -4x^-1/2

Answer 20

+1/x^3/2

Answer 21

4x^1/2 - 4x^-1/2 + 1/x^3/2

Answer 22

Yep. Now just integrate those 3.

Answer 23

how do you do anti-d for 1/x^3/2