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Mathematics 14 Online
OpenStudy (anonymous):

Definite Integral Question?

OpenStudy (anonymous):

Suppose \[\int\limits_{1}^{3} g(t)dt = 12\]

OpenStudy (anonymous):

Find \[\int\limits_{5}^{15} g(x/5)\]

OpenStudy (anonymous):

I know the answer is 16 but i dont know how to get it

OpenStudy (anonymous):

same with \[\int\limits_{-1/3}^{1/3} g(2-3t)dt\]

OpenStudy (anonymous):

answer is 60 not 16

zepdrix (zepdrix):

Let's keep this in our back pocket, we'll come back to it later: \[\Large\bf\sf \color{#DD4747 }{\int\limits\limits_{1}^{3} g(t)dt \quad=\quad 12}\] So we need to figure this out: \[\Large\bf\sf \int\limits\limits_{5}^{15} g\left(\frac{x}{5}\right)dx\] We'll start by making a substitution:\[\Large\bf\sf u=\frac{x}{5}\]What do you get for your dx?

OpenStudy (anonymous):

x^2/10

zepdrix (zepdrix):

Hmm no.. maybe I didn't ask the question clearly. We're just taking the derivative of our u.\[\Large\bf\sf du=\frac{1}{5}dx\qquad\to\qquad 5du=dx\]Does that make sense?

OpenStudy (anonymous):

ohh okay yeah

zepdrix (zepdrix):

Then we'll also want to change the boundaries of our function:\[\Large\bf\sf x=5:\qquad u=\frac{5}{5}=1\]\[\Large\bf\sf x=15:\qquad u=\frac{15}{5}=3\]

zepdrix (zepdrix):

So plugging all of these goodies in gives us:\[\Large\bf\sf 5\color{#DD4747 }{\int\limits\limits_{u=1}^3 g(u)\;du}\]

zepdrix (zepdrix):

Hmm it's starting to look familiar, yes? :o

OpenStudy (anonymous):

Yeah! thanks you really helped me make sense of this

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