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@Directrix
nope
the equation of a line in the y-intercept form y=mx+b the value of your m is your slope.
Okay, so then y=-2x+4
and m=slope so slope =-2
that is not what your question indicates earlier you had y= 2x + 4 if you changed it to y = -2x + 4 the slope changes from 2 to -2
Yeah, I've changed my mind :D
I've chosen a different answer
Still the same question though. I just changed my answer from -1/2 to -2
nope
-1/2, -2 and 2 are completely different values
Okay, so I got it wrong. So the answer is -2?
a negative slope goes downward from left to right looking like this symbol \ a positive slope goes upward from left to right looking like this symbol / and the value itself will determine how steep or flat a slope is
Oh okay!
let us say I have an equation y = 4x + 5 my slope would be 4 if I had an equation y = -5x + 3/2 then my slope is -5
That makes sense
you see the pattern here?
Whatever is the m, is the slope
the format of the equation itself is designed for you to identify the slope itself- the m value, and the y-intercept value, which b
But my equation is not in slope intercept form.
Wait, we gotta find the line that's perpendicular!
so if you are given 2x + 3y = 4 convert this first into the y-intercept format by solving for y -2x + 2x + 3y = 4 - 2x becomes 3y = -2x + 4 divide both sides my 3 y = -2x/3 + 4/3 so your slope is -2/3
perpendicular to what? remember that perpendicular line would involve 2 lines that makes a 90 degree angle from any reference point
So then slope=-2 -2*-1=2 Then -2 is perpendicular to the answer, 2
Oops! I mean -2*1/2=-1 Then perpendicular is 1/2
if you are to look for a line "perpendicular" to another line you obtain the negative reciprocal of the original line
if you have -3 as your original slope, a perpendicular line would be solved like this: negative reciprocal - (-1/3) = 1/3
Okay, I'm more confused then when I started. 1/3 isn't an answer option. thanks anyways, and have a great day.
because I am providing a different example from what you are given
if I kept telling you the answer, you would just rely on my answers and not think anymore I am giving you a different problem of the same concept so that you think for yourself and see if you truly understand
Oh this is a different problem?
I usually provide a different problem to explain a concept to someone
Don't worry. I'm not "getting" the answers from anybody. I did my work myself, so I did give it all my best shot, and I did put effort into it. I just needed someone to check it. Thanks for being through though. :D
Have a blessed day! :D
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