Question

Please help with this calc question...

Answer 1

http://assets.openstudy.com/updates/attachments/52aec7f5e4b0b09acc80047f-anneflys-1387186175051-screenshot20131216at1.34.55am.png

Answer 2

How does dN/dt become different as N(0) = 200 vs. N(0) = 1500?

Answer 3

it changes the constant when you find the anti derivative

Answer 4

I would start with
\[\frac{dN}{dt}=N-\frac{1}{1000}N^2\] and find the general anti derivative as
\[N(t)=\frac{N^2}{2}-\frac{n^3}{3000}+C\]

Answer 5

\(\frac{dN}{dt}\) does not "become different" it is the same in either case
\(N(0)=200\) means that \[N(t)=\frac{N^2}{2}-\frac{n^3}{3000}+200\]

Answer 6

wouldn't N(0) = 200 mean that N is 200 when t = 0?