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Solve, using the substitution method. 4x + 2y = 11 x – 2 = – 2y
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x – 2 = – 2y Solve for \(x\). \[x = -2y + 2\]
Now input that value into the first equation.
\[4-2y + 2 + 2y = 11\] Move all the like terms to one side.
@zobobozo Can you do that?
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Wait, sorry forgot the round brackets... \[4(-2y + 2) + 2y = 11\]
Is that what you got? Odd I got: \[x = 3,~y = \dfrac{-1}{2}\]
\[4(-2y + 2) + 2y = 11\] Simplifies to: \[y = \dfrac{-1}{2}\]
Then: \[x – 2 = – 2y\] Input -1/2: \[x – 2 = – 2\dfrac{-1}{2}\] Simplifies to: \[x = 3\]
no its 3 and -1/2
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Uh, I said that? \[x = 3\] \[y = \dfrac{-1}{2}\] If you wanted to write that in a pair it would look like: \[3, \dfrac{-1}{2}\]
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