Question

Given the equation −4 sqrt x-3 = 12, solve for x and identify if it is an extraneous solution.

x = 0, solution is not extraneous

x = 0, solution is extraneous

x = 12, solution is not extraneous

x = 12, solution is extraneous

Answer 1

@kewlgeek555 @AllTehMaffs can you help at all?

Answer 2

I don't unerstand the equation. Is it:\[\sqrt[-4]{x ^{-3}}=12\]

Answer 3

I think it'd be
\[-4\sqrt{x-3}=12\]

Answer 4

You get a complex solution

Answer 5

That doesn't give the right solutions though. Hmm....

Answer 6

if it's
\[\sqrt[-4]{x^{-3}} = 12\]
\[ (x^{-3})^{-1/4}=12\]
\[(x^{-3})^{-1} = 12^4\]
\[x^3=12^4\]
that gives a weird answer :P

I can't figure out where they're getting either 0 or 12, however :P