Consider three force vectors ~ F1 with magni- tude 58 N and direction 63 , ~ F2 with magni- tude 30 N and direction −160 , and ~ F3 with magnitude 29 N and direction 140. All direc- tion angles are measured from the positive x axis: counter-clockwise for 0 and clock- wise for

Question

Consider three force vectors ~ F1 with magni-
tude 58 N and direction 63 , ~ F2 with magni-
tude 30 N and direction −160 , and ~ F3 with
magnitude 29 N and direction 140. All direc-
tion angles  are measured from the positive
x axis: counter-clockwise for  > 0 and clock-
wise for  < 0.
What is the magnitude F of the net force
vector ~F
= ~ F1 + ~ F2 + ~ F3?
Answer in units of N


What is the direction of ~F
as an angle be-
tween the limits of −180 and +180 from the
positive x axis with counterclockwise as the
positive angular direction.
Answer in units of degre

anonymous · Answer

attachment

anonymous · Answer

Break each force into its components on the x, y axes (Fx, Fy)

Fx = F cos(@), Fy = F sin(@)

Then add the forces by these components, F is (sum of Fx, sum of Fy)

Get direction from @ = arc tan (sum Fy/ sum Fx)

anonymous · Answer

The final answer should be all of forces combined?

anonymous · Answer

Right. "Net force."