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70 ml of water is added to 15 ml of a 0.48 mol/l solution of sulfuric acid. Find the concentration of the dilution?
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the answer is supposed to be 0.08 mol/l but i don't know how to get there
when you're diluting a concentrated solution, a handy relationship to remember is: \[M_1*V_1 = M_2*V_2\]where \(M_1\) and \(V_1\) are the concentration and volume of the concentrated stuff and \(M_2\) and \(V_2\) are the concentration and volume of the diluted form. You know 3 of the 4 pieces, find the fourth
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