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Mathematics 7 Online
OpenStudy (anonymous):

a^2+2a-3=0

OpenStudy (anonymous):

What are you trying to do with it solve it?

OpenStudy (mathstudent55):

Use the quadratic formula.

OpenStudy (anonymous):

^ if solving that

OpenStudy (anonymous):

its solving quadratic equations by completing the square

OpenStudy (mathstudent55):

Ok, I'll show it to you step by step.

OpenStudy (anonymous):

ive got it to a^2 +2a +1 =4 if thats right

OpenStudy (mathstudent55):

The first step is to move the constant term (the number) to the right side. Add 3 to both sides. Leave a space on the left side where the number used to be.

OpenStudy (mathstudent55):

Looks good to me.

OpenStudy (mathstudent55):

Now you rewrite the left side as the square of a binomial.

OpenStudy (anonymous):

(a+1)^2?

OpenStudy (mathstudent55):

Yes.

OpenStudy (anonymous):

kk thanks

OpenStudy (mathstudent55):

So you have (a + 1)^2 = 4

OpenStudy (anonymous):

yeah and then yiu square root it and move the one?

OpenStudy (mathstudent55):

Now you use the idea below: \(x^2 = k ~~~\rightarrow ~~~x = \pm\sqrt{k}\)

OpenStudy (anonymous):

right.

OpenStudy (mathstudent55):

Yes, you do take the square root of both sides, but you get the square root of the left side equal the plus/minus square root of the right side. \( (a + 1)^2 = 4\) \(a + 1 = \pm 2\) \(a + 1 = 2 ~~\lor~~ a + 1 = -2 \) Now you solve each equation.

OpenStudy (anonymous):

a=-2,-1

OpenStudy (mathstudent55):

God job!

OpenStudy (anonymous):

Thanks for the help.[=

OpenStudy (mathstudent55):

You're welcome.

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