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OpenStudy (anonymous):
What are you trying to do with it solve it?
OpenStudy (mathstudent55):
Use the quadratic formula.
OpenStudy (anonymous):
^ if solving that
OpenStudy (anonymous):
its solving quadratic equations by completing the square
OpenStudy (mathstudent55):
Ok, I'll show it to you step by step.
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OpenStudy (anonymous):
ive got it to a^2 +2a +1 =4 if thats right
OpenStudy (mathstudent55):
The first step is to move the constant term (the number) to the right side.
Add 3 to both sides. Leave a space on the left side where the number used to be.
OpenStudy (mathstudent55):
Looks good to me.
OpenStudy (mathstudent55):
Now you rewrite the left side as the square of a binomial.
OpenStudy (anonymous):
(a+1)^2?
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OpenStudy (mathstudent55):
Yes.
OpenStudy (anonymous):
kk thanks
OpenStudy (mathstudent55):
So you have
(a + 1)^2 = 4
OpenStudy (anonymous):
yeah and then yiu square root it and move the one?
OpenStudy (mathstudent55):
Now you use the idea below:
\(x^2 = k ~~~\rightarrow ~~~x = \pm\sqrt{k}\)
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OpenStudy (anonymous):
right.
OpenStudy (mathstudent55):
Yes, you do take the square root of both sides, but you get the square root of the left side equal the plus/minus square root of the right side.
\( (a + 1)^2 = 4\)
\(a + 1 = \pm 2\)
\(a + 1 = 2 ~~\lor~~ a + 1 = -2 \)
Now you solve each equation.
OpenStudy (anonymous):
a=-2,-1
OpenStudy (mathstudent55):
God job!
OpenStudy (anonymous):
Thanks for the help.[=
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