Can you proof this identity briefly enough? without posting links please.
\[\huge\color{blue}{\huge {\bbox[5pt,lime,border:2px solid purple]{Log_27=\frac{Log_{10}7}{Log_{10}2}}}}\]
I am leaving for an hour..
change of base theorem I suck at proofs :(
\( \log_2 7 = x \iff 2^x = 7\) \(\log_{10} 7 = y \iff 10^y = 7\) \(y = \log_{10} 7 \) \(~~= \log_{10}{2^x} \) \(~~= x\log_{10}{2}\) \( y= \log_2 7 \log_{10} 2\) \( \log_{10} 7= \log_2 7 \log_{10} 2\) \( \dfrac{\log_{10}7 }{\log_{10} 2} = \log_2 7\)
WOW! NICE AND CLEAR!
wlcm
@jim_thompson5910 @phi @myininaya can you give math student a medal for appreciation?
Really awesome, and brief I like that, and without unnecessary words...
how do you give medals?
It's just the definition of logs, a property of logs, and substitution. Then a little algebra to finish it off.
Yes. You can give medals to students. I do sometimes when they put forth a good effort.
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