Question

Simplifying Radicals Help...

Answer 1

May I be of assistance?

Answer 2

\[\sqrt{80x ^{7}y ^{24}}\] my teacher got \[4y ^{12}\sqrt{5x7}\]

Answer 3

oops wrong one

Answer 4

\[4x ^{3}y ^{12}\sqrt{5} \] no actually this is what she got (Sorry for the confusion)

Answer 5

I think the x should go inside the radical instead, am I right or wrong?

Answer 6

Well you need to break it down into components where the x or y with exponents can get rid of them so think of the problem like this \[\sqrt{80}\sqrt{x^2}\sqrt{x^2}\sqrt{x^2}\sqrt{x^1}\sqrt{y^2}\sqrt{y^2}\sqrt{y^2}\sqrt{y^2}\sqrt{y^2}\sqrt{y^2}\sqrt{y^2}\] (the y part goes on for 12 total)

If you then undo the roots and simplify the 80 you get \[4\sqrt{5}* x*x*x*\sqrt{x}*y*y*y*y*y*y*y*y*y*y*y*y\]

Which simplifies into
\[4x^{3}y^{12}\]

Answer 7

woops forgot the

\[\sqrt{5x}\]
on the end

Answer 8

thanks, but I forgot to mention the original= \[\sqrt{80x ^{7}y ^{24}}\]

Answer 9

nah you told me that

Answer 10

oooooh ok so the x goes inside the radical, right?

Answer 11

sorry lol I was a little lost hah XD

Answer 12

yes it does since when you break them into x^2 inside radicals there must be one that still is just x in a radical so if u combined them again you got x^7 in a radical like the original. If that makes sense

Answer 13

Yes, perfectly, that's what I got at first lol, but my teacher got it wrong lol thanks so much :D

Answer 14

She said the x went outside the radical along with 4y lol

Answer 15

:) but know I the right answer and am ready for my test tomorrow :p