Solve each system using substitution. Tell whether the system has one solution, infinitely many solutions, or no solution. -x =+ y = -13 3x - y = 19
can u plz recheck your first equation
I don't think I typed anything wrong. this is what my question said soooo
hmm the fist equation says -x =+ y = -13 ..there must only be one equal sign in a equation
I'm sorry,you're right. take out the equal sign
which equal sign
I'll retype the whole thing for you. Solve each system using substitution. Tell whether the system has one solution, infinitely many solutions, or no solution. -x + y = -13 3x - y = 19
lets make y the subject in the first equation \[y=x-13\] then lets 'substitute' x=13 into the second equation instead of the y \[3x-(x-13)=19\]
\[3x-x+13=19\]
so whats the answer? :)
3x−x+13=19 \[2x=6\] lets solve for x
get x alone distribute the negative then plug x into the other equation once you solve for y plug into other equation and solve
so at x=3. this means that at x=3 the graphs intersect
we can find the y coordinate by plugging in x=3 into any of the two original equations
What is your final answer (your coordinate) where the graphs intersect?
and from this u can tell how many times solutions this system of equations have (i.e how many intersections)
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