Question

FACTORING BY GROUPING;;
12p^3-21p^2+28p-49
i got p^2(12-21) and now im STUCCCK

Answer 1

cant factor the p^2 out like that
look at the term with 21 and -49 group them.
look at the term with 12 and 28 and group them and factor
notice the common factors?

Answer 2

like 12p^3+28p-21p-49?, and then take out common factors ?

Answer 3

no
(12p^3+28p)
(-21p^2-49)
factor these individually

Answer 4

2p(6p^2+14) [first] ?

Answer 5

thats an example

Answer 6

you can pull a 4p out of that

Answer 7

4p(3p^2+7) ?

Answer 8

yep, now do the next one

Answer 9

7(-3p^2-7) ?

Answer 10

pull out a -7

Answer 11

4p(3p^2+7)-7(3p^2+7) ?

Answer 12

now you have 2 binomials
4p-7
3p^2+7
you're factored
just make sure these aren't factor. like the difference or sum of 2 squares. sometimes they are and they will trick you

Answer 13

they arent.

Answer 14

so your problem is completed.

Answer 15

thanks

Answer 16

my pleasure.