Question

o

Answer 1

Can you list all the givens based on that sigma that you have?

Answer 2

hld on is that 2 to the i or 2 to the 1 at the end?

Answer 3

a2=5 times 2^2=20 not 40.

Answer 4

r=2

Answer 5

\[A_1=10\]\[A_2=20\]\[r=2\]\[n=10\]

Answer 6

Sorry for the disconnection.

Answer 7

\[S_n=A_1( \frac{1-r^n}{1-r} )\]plug in numbers

Answer 8

\[S_n=10( \frac{1-2^{10}}{1-2} )=10\frac{1-1024}{1-2}=10\frac{-1023}{-1}=10 \times (1023)\]CORRECT.

Answer 9

Just tell me one thing, if it was with same conditions but infinite what would you say?

Answer 10

and yes I can help you with a similar prob.

Answer 11

Same thig, tell me everything based on the sigma.

Answer 12

yes

Answer 13

\[n=∞\]\[A_1=(2/3)\]\[A_2=(4/9)\]\[r=(2/3)\]AGREE?

Answer 14

Can you tell me if it converges or diverges, and explain?

Answer 15

and why?

Answer 16

OK

Answer 17

So lets use.\[S_n=\frac{A_1}{1-r}\]

Answer 18

\[S_n=\frac{2/3}{1-2/3}=\frac{2/3}{1/3}=2\]

Answer 19

Then no sum.

Answer 20

Anytime, ty for refreshing me...

Answer 21

Too it last yr with a 97 on exam LOVE MATH!!!!!!!!!!

Answer 22

I mean took trig