In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 14 vowels and 22 consonants, what is the probability you will choose a vowel then a consonant ?
@hartnn @haitianmontana
@Salmon are you able to teach me how this is done?
In total their are 36 letters right??
Yeah
First we will find our sample space In how many ways you can select the first letter??
14/36 because they want a vowel first.
Ok...you are actually approaching the answer in different way but even your method is right.. Lets proceed in your way... Now find the probability of choosing a consonant...
22/36
now the probability that you will choose a vowel then a consonant is the product of their individual probabilities i.e probability that you will choose a vowel then a consonant=(probability of chossing a vowel)(probability of choosing a consonant)
?
What is the probability of chossing a vowel?
14
you mean 14/36?
mhmm
probability of choosing a consonant= 22/36 so your answer is (14/36)(22/36)=???
idk 308/36????
\[\frac{ 14 }{ 36 }\times \frac{ 22 }{ 36 }=\frac{ 14\times22 }{ 36\times36 }=\frac{ 308 }{ 1296 }\]
i tried that it doesn't work....
either that or i can't simplify... but whatever i give up
k..lets start again....This time in an systematic way...
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