You must:

Label and display your new polynomial identity
Prove that it is true through an algebraic proof, identifying each step
Demonstrate that your polynomial identity works on numerical relationships

WARNING! No identities used in the lesson may be submitted. Create your own. See what happens when different binomials or trinomials are combined. Below is a list of some sample factors you may use to help develop your own identity.

Question

You must:

    Label and display your new polynomial identity
    Prove that it is true through an algebraic proof, identifying each step
    Demonstrate that your polynomial identity works on numerical relationships

WARNING! No identities used in the lesson may be submitted. Create your own. See what happens when different binomials or trinomials are combined. Below is a list of some sample factors you may use to help develop your own identity.

anonymous · Answer

sample factors I can use....

    (x – y)
    (x + y)
    (y + x)
    (y – x)
    (x + a)
    (y + b)
    (x^2 + 2xy + y^2)
    (x^2 – 2xy + y^2)
    (ax + b)
    (cy + d)

anonymous · Answer

from the warning not to use any in the lesson, I'd say just stay with the given samples.

ganeshie8 · Answer

just cookup some identity

ganeshie8 · Answer

maybe try to derive a formula for directly calculating :-
(ax + b)(cx + d)

anonymous · Answer

I'm back, and I'm kind of confused on that lol

anonymous · Answer

An identity is like breaking down a equation so that you end up with a number being equal to the same number right?

ganeshie8 · Answer

did u get wat the question is asking us to do ? :)

anonymous · Answer

I need to create a identity and prove it through algebra I guss lol

ganeshie8 · Answer

An identity can be a formula, that u can use to save time.

anonymous · Answer

so I need to make up a formula lol?

ganeshie8 · Answer

for ex, below is an identity :-
(a + b)(a - b) = a^2 -  b^2

anonymous · Answer

lol idk what to make

ganeshie8 · Answer

read my second reply

ganeshie8 · Answer

make a formula for that

anonymous · Answer

(ax + b)(cx + d)

how about...
acx + bd?

ganeshie8 · Answer

(ax + b)(cx + d)

FOIL it first,
then try to simplify

anonymous · Answer

umm

(ax + b)(cx + d)
acx^2 + adx + bcx +bd

anonymous · Answer

brb real quick, lunch...

ganeshie8 · Answer

yes, we're done :-

just take out x common

ganeshie8 · Answer

(ax + b)(cx + d)

FOILing it :-
acx^2 + adx + bcx +bd

taking x common in middle two terms :-
acx^2 + (ad+bc)x + bd

ganeshie8 · Answer

so ur new polynomial identity is :-
(ax+b)(cx+d) = acx^2 + (ad+bc)x + bd

ganeshie8 · Answer

Enjoy ur lunch...

anonymous · Answer

ok I'm back

anonymous · Answer

Hey can you help me use this with a numerical equation now?

anonymous · Answer

@ganeshie8