Question

using l'hopital's rule:

lim x goes to 0+ " from the right " for f(x)=xLnx

please check my answer :

we simplify it to get lnx/1/x

then we evaluate to get infinity over infinity

then :

1/x/-1/x^2

1/x * x^-2/1 x goes with x^-2 to get x^-1
lim x goes to +0 , x^-1/1 = 0

Answer 1

Thanks I solved it ,