Question

help?!?!(medal will be given)

Calculate the area of triangle QRS with altitude ST, given Q (0, 5), R (−5, 0), S (−3, 4), and T (−2, 3).


6.2 square units

7 square units

5.9 square units

5 square units

Answer 1

@esshotwired @phi help plz

Answer 2

@esshotwired

Answer 3

@phi

Answer 4

Did you plot the points to see what it looks like ?

Answer 5

it looks like triangle

Answer 6

Here is a graph of the problem
to find the area of the triangle, you need to find the length of its base QR
use the distance formula
and the length of its altitude ST
use the distance formula

can you do that ?

Answer 7

QR= (0,5),(-5,0)
=SQUAR ROOT (X2-X1)2+(Y2-Y1)2
(-5-0)2+(0-5)2=25+25=50=7.071

Answer 8

yes, but in this case, you might want to write it as
\[ \sqrt{50} = \sqrt{2\cdot 25} = 5\sqrt{2} \]

do the same for ST.
(leave it in radical form)

then do
area (of a triangle) = 1/2 * base * height

Answer 9

ST=(-3,4),(-2,3)
-2--3^2+3-4^2=
1+1=2

Answer 10

don't forget the square root

Answer 11

SQUAR ROOT 2 =1.41

Answer 12

but leave it \( \sqrt{2} \)

now what is the area?
\[ A= \frac{1}{2} \cdot base \cdot { height } \\
= \frac{1}{2} \cdot 5 \sqrt{2} \cdot \sqrt{2}
\]
notice that \( \sqrt{2} \cdot \sqrt{2} = 2\)

Answer 13

5

Answer 14

THX FOR THE HELP

Answer 15

yw