What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

Question

campbell_st · Answer

well the distance from the centre to the point is the radius 

the standard form is 

$$(x - h)^2 + (y - k)^2 = r^2$$

(h, k) is the centre and r is the radius... 

you know h = -2 and k = -3   and you can find r... 

so substitute and perhaps expand... 

hope this helps

theislander · Answer

would it be 
(x − 2)2 + (y − 3)2 = 16
or
(x − 2)2 + (y − 3)2 = 4

@campbell_st

campbell_st · Answer

the distance from the centre (-2, -3) to (-2, 0) is 3 units up

so the equation is

(x + 2)^2 + (y + 3)^2 = 3^2