Please help me I will give medal and become fan if you explain. Find the equation of the graph that is parallel and perpendicular that passes through the specified point. 4x + 3y = 12 (-1,-1)

Question

Please help me I will give medal and become fan if you explain.      Find the equation of the graph that is parallel and perpendicular that passes through the specified point.             4x + 3y = 12 (-1,-1)

anonymous · Answer

@esshotwired Do you know how to do this?

anonymous · Answer

@kewlgeek555 @lauluisa @timaashorty @InYourHead @brendalopez @e.cociuba @TuringTest

esshotwired · Answer

so u need 2 lines that pass through (-1, -1)?? parallel and perpendicular?

anonymous · Answer

I guess lol I am so confused and that was all that the question gave me.

esshotwired · Answer

umm ok well...im gunna think to myself and u just read it until i ask u a question

anonymous · Answer

k

esshotwired · Answer

4x + 3y = 12
3y=-4x+12
y=-4/3x+12

parallel: -4/3x
perp: 3/4x

esshotwired · Answer

y+1=-4/3(x+1)
y+1=-4/3x-4/3
y=-4/3x-7/3

parallel ^^

esshotwired · Answer

y+1=3/4(x+1)
y+1=3/4x+3/4
y=3/4x+7/4

perpendicular ^^

anonymous · Answer

how you get that? The last one?

the_fizicx99 · Answer

@esshotwired perp is the reciprocal and negative i.e 3x -> -1/3x

esshotwired · Answer

the slope of a line perpendicular to another line is the opposite reciprocal. meaning you flip the fraction and times it by -1. if it is not a fraction then the number will be the denominator with a 1 on top.

anonymous · Answer

oh but where did the (x=1) come from?

esshotwired · Answer

you mean (x+1)? it is part of the point slope form: $$y-y ^{1}=slope(x-x ^{1})$$