Question

Help? How many real and imaginary zeros does this have?

Answer 1

Where is the algebraic expression?

Answer 2

I can't figure this one out for some reason...
f(x) = x^5 + 7x^4 + 2x^3 + 14x^2 + x + 7

Answer 3

Can you figure it out? :/

Answer 4

@robtobey

Answer 5

Maximum number of real and imaginary solutions is the magnitude of the largest power. In this case, 5.

Answer 6

I know that.. But when I work it out, I only get four.. I can't figure this one out. :c

Answer 7

Mathematica gives the following for the factors.\[(x+7) \left(x^2+1\right)^2 \] There is only one real root, x = -7
Refer to the Mathematica attachment.

Answer 8

I didn't understand that.

Answer 9

The other four roots imaginary.

Answer 10

Okay..