Question

If f(x) = (x^2+1)^x, then f'(x) = ?

Answer 1

It's asking you to derive
(x^2+1)^x

Answer 2

can someone post the steps to solving this problem?

Answer 3

http://www.derivative-calculator.net/

Answer 4

paste your problem there....

Answer 5

thanks you

Answer 6

Pretty soon we will not have to think at all ;)

Answer 7

(d/dx) (x^n) = (n)(x^(n-1)) very handy.
(d/dx)(x^3) = 3x^2.

Answer 8

\[f(x)=(x^2+1)^x\]
Logarithmic differentiation:
\[\ln f(x)=\ln (x^2+1)^x\\
\ln f(x)=x\ln (x^2+1)\]
Differentiate both sides with respect to \(x\):
\[\frac{f'(x)}{f(x)}=\ln(x^2+1)+x\left(\frac{2x}{x^2+1}\right)\]
Solve for \(f'(x)\).