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Mathematics 8 Online
OpenStudy (anonymous):

Find the value of (f ◦ g)' at the given value of x (attachment)

OpenStudy (anonymous):

OpenStudy (hitaro9):

1/6

OpenStudy (hitaro9):

u equals 7x-x^2, so you can substitute that any place where u is.

OpenStudy (hitaro9):

so f(x) = 1/ 7x-x^2

OpenStudy (hitaro9):

And since x=1, you can substitue that in anywhere

OpenStudy (anonymous):

thats not an answer choice. 1/5 -1/5 -5/36 5/36

OpenStudy (hitaro9):

so f(1) = 1/(7(1)-1^2) 1/6

OpenStudy (hitaro9):

Oh

OpenStudy (hitaro9):

Hm

OpenStudy (hitaro9):

Could it be that your teacher made a typo?

OpenStudy (hitaro9):

Or when you say (f ◦ g)', is that asking for the derivative? I assumed it was a typo?

OpenStudy (anonymous):

i dont know. the derivative of 1/6 is 0....

OpenStudy (hitaro9):

Ah, but if you take the derivative of 1/(7x-x^2) and then plug in 1

OpenStudy (hitaro9):

I'll bet that's your answer. I though that ' was a typo.

OpenStudy (hitaro9):

So to take the derivative of (7x-x^2)^-1 we're going to need to use the chain rule So I like to work outside inwards, so outside we find -(7x-x^2)^-2 times the inside derivative

OpenStudy (hitaro9):

-(7x-x^2)^-2 (7-2x)

OpenStudy (hitaro9):

and then plug in 1

OpenStudy (anonymous):

ok i got -5/36. thank you so much!

OpenStudy (hitaro9):

No problem

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