Find the value of (f ◦ g)' at the given value of x (attachment)
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OpenStudy (anonymous):
OpenStudy (hitaro9):
1/6
OpenStudy (hitaro9):
u equals 7x-x^2, so you can substitute that any place where u is.
OpenStudy (hitaro9):
so f(x) = 1/ 7x-x^2
OpenStudy (hitaro9):
And since x=1, you can substitue that in anywhere
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OpenStudy (anonymous):
thats not an answer choice.
1/5
-1/5
-5/36
5/36
OpenStudy (hitaro9):
so f(1) = 1/(7(1)-1^2)
1/6
OpenStudy (hitaro9):
Oh
OpenStudy (hitaro9):
Hm
OpenStudy (hitaro9):
Could it be that your teacher made a typo?
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OpenStudy (hitaro9):
Or when you say (f ◦ g)', is that asking for the derivative? I assumed it was a typo?
OpenStudy (anonymous):
i dont know. the derivative of 1/6 is 0....
OpenStudy (hitaro9):
Ah, but if you take the derivative of 1/(7x-x^2) and then plug in 1
OpenStudy (hitaro9):
I'll bet that's your answer. I though that ' was a typo.
OpenStudy (hitaro9):
So to take the derivative of (7x-x^2)^-1 we're going to need to use the chain rule
So I like to work outside inwards, so outside we find
-(7x-x^2)^-2 times the inside derivative
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