Find the value of (f ◦ g)' at the given value of x (attachment)
1/6
u equals 7x-x^2, so you can substitute that any place where u is.
so f(x) = 1/ 7x-x^2
And since x=1, you can substitue that in anywhere
thats not an answer choice. 1/5 -1/5 -5/36 5/36
so f(1) = 1/(7(1)-1^2) 1/6
Oh
Hm
Could it be that your teacher made a typo?
Or when you say (f ◦ g)', is that asking for the derivative? I assumed it was a typo?
i dont know. the derivative of 1/6 is 0....
Ah, but if you take the derivative of 1/(7x-x^2) and then plug in 1
I'll bet that's your answer. I though that ' was a typo.
So to take the derivative of (7x-x^2)^-1 we're going to need to use the chain rule So I like to work outside inwards, so outside we find -(7x-x^2)^-2 times the inside derivative
-(7x-x^2)^-2 (7-2x)
and then plug in 1
ok i got -5/36. thank you so much!
No problem
Join our real-time social learning platform and learn together with your friends!