Algebra help please

Question

Algebra help please

anonymous · Answer

$$\frac{ 2x }{ (3x+1) } \times \frac{ x+3 }{ x-1 }$$

anonymous · Answer

@ranga  Please help, I've been doing this for a few hours and I only have 3 left

anonymous · Answer

it's rational expressions

ranga · Answer

multiply the top.  multiply the bottom.
You can leave it as factors or you can FOIL it.
2x(x+3) / {(3x+1)(x-1)}   You can leave it like this.  But if they want you to multiply it out then:

ranga · Answer

= (2x^2 + 6x) / (3x^2 - 2x - 1)

anonymous · Answer

Sorry I was writing it down so I can follow along :) So is that the simplied version of the first fraction?

anonymous · Answer

@ranga

solomonzelman · Answer

you can't simplify them, you can expand it by multiply the numerators and denominators together the way ranga did, but not cancel anything out.

anonymous · Answer

So is the last thing he said the numerator and denominator of the equations multiplied together?

solomonzelman · Answer

that's what he did to get it.
$$\frac{(2x)~~\times~~(x+3)}{(3x+1)~~\times~~(x-1)}$$

anonymous · Answer

Thank you so much, can you help me with just two more? It's my last 2 and i've been on this for hours and it has to be done by tomorrow

anonymous · Answer

I would appreciate it please