MEDAL GIVEN TO CORRECT ANSWER. Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane? A. 670 N B. 493 N C. 603 N D. 552 N
Since the skier is going down a sloped hill, the whole weight will not need to be supported by the hill.
This one is tricky to explain because I can't draw a picture.
You can if you it the draw button under the response box.
I'm on an iPad and don't think that button is available on my os.
The angle of the slope of the hill would be the same angle between the line perpendicular to the hill and the force of gravity vector (42 deg).
So, cos(42 deg) = n/902
Make sense?
where did you get 902? I'm still not understanding what the answer should be. @JoannaBlackwelder
902 is mg
n would be the component of the weight that is perpendicular to the hill.
The normal force is the force the hill is pushing back on the skier. Its magnitude would be the same, but the opposite direction.
is it C?
I get closer to A
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