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Physics 8 Online
OpenStudy (anonymous):

MEDAL GIVEN TO CORRECT ANSWER. Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane? A. 670 N B. 493 N C. 603 N D. 552 N

OpenStudy (joannablackwelder):

Since the skier is going down a sloped hill, the whole weight will not need to be supported by the hill.

OpenStudy (joannablackwelder):

This one is tricky to explain because I can't draw a picture.

OpenStudy (anonymous):

You can if you it the draw button under the response box.

OpenStudy (joannablackwelder):

I'm on an iPad and don't think that button is available on my os.

OpenStudy (joannablackwelder):

The angle of the slope of the hill would be the same angle between the line perpendicular to the hill and the force of gravity vector (42 deg).

OpenStudy (joannablackwelder):

So, cos(42 deg) = n/902

OpenStudy (joannablackwelder):

Make sense?

OpenStudy (anonymous):

where did you get 902? I'm still not understanding what the answer should be. @JoannaBlackwelder

OpenStudy (joannablackwelder):

902 is mg

OpenStudy (joannablackwelder):

n would be the component of the weight that is perpendicular to the hill.

OpenStudy (joannablackwelder):

The normal force is the force the hill is pushing back on the skier. Its magnitude would be the same, but the opposite direction.

OpenStudy (anonymous):

is it C?

OpenStudy (joannablackwelder):

I get closer to A

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