MEDAL GIVEN TO CORRECT ANSWER.
Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane?
A. 670 N
B. 493 N
C. 603 N
D. 552 N
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OpenStudy (joannablackwelder):
Since the skier is going down a sloped hill, the whole weight will not need to be supported by the hill.
OpenStudy (joannablackwelder):
This one is tricky to explain because I can't draw a picture.
OpenStudy (anonymous):
You can if you it the draw button under the response box.
OpenStudy (joannablackwelder):
I'm on an iPad and don't think that button is available on my os.
OpenStudy (joannablackwelder):
The angle of the slope of the hill would be the same angle between the line perpendicular to the hill and the force of gravity vector (42 deg).
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OpenStudy (joannablackwelder):
So, cos(42 deg) = n/902
OpenStudy (joannablackwelder):
Make sense?
OpenStudy (anonymous):
where did you get 902?
I'm still not understanding what the answer should be. @JoannaBlackwelder
OpenStudy (joannablackwelder):
902 is mg
OpenStudy (joannablackwelder):
n would be the component of the weight that is perpendicular to the hill.
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OpenStudy (joannablackwelder):
The normal force is the force the hill is pushing back on the skier. Its magnitude would be the same, but the opposite direction.