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Mathematics 13 Online
OpenStudy (anonymous):

Can someone please help me with this problem? I'd really appreciate the help. Express the length of the curves as an integral, but do not evaluate. x= t^2, y= cos(pit), for 0 is less than or equal to t less than or equal to 1

OpenStudy (anonymous):

The formula is \[ \int_0^1 \sqrt{ x'(t)^2 + y'(t)^2}dt \]

OpenStudy (anonymous):

Can you finish it now?

OpenStudy (mathmale):

Nice work, Elias. Anything you can do to emphasize that that "dt" is outside the square root operator, not underneath it?

OpenStudy (anonymous):

outside

OpenStudy (anonymous):

Yes thank you very much @eliassaab

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