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Can someone please help me with this problem? I'd really appreciate the help. Express the length of the curves as an integral, but do not evaluate. x= t^2, y= cos(pit), for 0 is less than or equal to t less than or equal to 1
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The formula is \[ \int_0^1 \sqrt{ x'(t)^2 + y'(t)^2}dt \]
Can you finish it now?
Nice work, Elias. Anything you can do to emphasize that that "dt" is outside the square root operator, not underneath it?
outside
Yes thank you very much @eliassaab
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