Question

a 4 Kg block is dropped from a height of 5 m . how much kinetic energy does it have when it hits the ground/

Answer 1

Kinetic Energy = \[\frac{ 1 }{ 2 }m v^{2} \]

calculate the speed v by using: \[v^{2} = u^{2} + 2as\]

Answer 2

It gets that kinetic energy from the loss of potential energy due to gravity and height = m g h.