You roll a pair of dice. What is the probability that both dice will show prime numbers
Look at this sample space for the 36 possible outcomes of a pair of dice toss. Count the instances of both die showing a prime number. The probability is that number divided by 36. @CharleeAnne
Note: 1 is NOT a prime number.
ok, thank you
So, what did you get for the answer?
i got 4/9
How many ordered pairs of primes did you count? I'm thinking you may have counted 16 pairs which is not correct. I counted only 6 but I may need to count again. Remember that both numbers have to be prime so a result such as (2,4) would not be counted.
im actually really confused by using this chart i dont really understand how to use it
When you toss 1 die, there are six possible outcomes. When you toss the second die, there are six possible outcomes. 6*6 = 36 are there are 36 possible outcomes for tossing a pair of dice.
i got that but i dont understand what i should do after that
Of these 36 possibilities, you want those with prime numbers on both die. I think I have 9 circled. See what you think. Click on the attachment.
So, the probability would be 9/36 where 9 is the number of successful outcomes and 36 is the number of possible outcomes. By success, it is meant whatever was a desired outcome, in this case, (prime, prime).
i thought 2 wasn't a prime number
The number 1 is not a prime number. 2 is the only even prime number. A prime number has exactly two positive factors, itself and 1.
oh ok
Here are the beginning prime numbers. There are infinitely many.
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