MEDAL The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price of two products, A and B, over time. The price f(x), in dollars, of product A after x years is represented by the function below. f(x) = 12500(0.82)x Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. (5 points) Part B: The table below shows the price f(t), in dollars, of product B after t years. t (number of years) 1 2 3 4 f(t) (price in dollars) 5600 3136 1756.16 983.45
can you help please
^_^ im doing that test right now
really do you have any idea how to solve it
if you dont we can work together to solve it
12500(0.82)=10250
is that for part b
so it is decreasing by 2250 its part a
oh ok
so for part b i have to find rate of change to find out the greatest percentage
im not so sure how to do that part
ok we can work on it together
are u ninth
yes
so i think we have to find the rate of change
i think its product b that has the highest percent of change because for product a its 2550
yes, so we have to plug it in.
so for product a: 12500(0.82) times year 2 would be 12500(0.82)^2 would be 12500(1.62)=20,250 so therefore it would be increasing
okay
so product a has the highest percentage
@melancholymushroom did you get this correct?
Did you guys get this right?
Why does everybody think a number less than 1 would multiply and become bigger?
I have no clue, but its the oppisite :( any1 know the correct answer? @IrishBoy123
both these are falling in price
and it seems to me that in order to do a comparison you need to replicate the table for product ie this table you have for B . do it also for A t (number of years) 1 2 3 4 f(t) (price in dollars) 5600 3136 1756.16 983.45
and then calculate the YoY drop in price so for Y 1 -> 2 for B \(\large \frac{3136-5600}{5600} \approx -44\% \)
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