Question

Question 21. 21. Find the equation of the tangent line to the curve f(x) = x2 + 2x at x = 1.

Answer 1

Take the derivative of f(x) and evaluate it at 1. This gives the slope. Then use y-y1=m(x-x1)

Answer 2

to get the equation of the line.

Answer 3

slope is 4 but what are y, y1, x and x1?

Answer 4

That equation is from algebra classes, remember when you learned slopes of lines, parallel and perpendicular lines etc. in grade 10 perhaps.

Answer 5

yes and it was grade 8 when i had algebra

Answer 6

Remember now or a refresher?

Answer 7

it was 4 years ago, and being sick isn't helping:(

Answer 8

Okay... you have X=1 what of y?

Answer 9

3?

Answer 10

No I asking to know whether its given

Answer 11

no

Answer 12

Something tells me the line is vertical. And vertical lines have undefined slopes. But find the slope first so we'll know for sure.

Answer 13

slope is 4

Answer 14

Okay the line is not vertical then. Lol.

Answer 15

Sorry...I'm just thinking the line should touch the curve at a point (x,y).

Answer 16

@hartnn

Answer 17

The slope is 4 and the line goes through the point (1,3)
y-3=4(x-1)
y-3=4x-4
y=4x-1

Answer 18

Apparently I forgot this simple procedure. But that's the equation.

Answer 19

Find the equation of the tangent line to the curve f(x) = x3 – 2x at x = 1.

Answer 20

1. Find the f(1). That is the point the tangent will go through
2. Find the first derivative
3. Evaluate the first derivative for x = 1. That is the slope of the tangent line at the point you found in step 1
4. Find the equation of the line with the slope you found in step 3 and the point you found in step 1

Answer 21

y=3x-4?

Answer 22

How did you get 3 for the slope?

Answer 23

derivative is 3x? isn't it?

Answer 24

f'(x)=3x-2

Answer 25

-2 derived is zero....

Answer 26

oh oops i forgot the x ....

Answer 27

All I have to go by is what you posted and you posted this: Find the equation of the tangent line to the curve f(x) = x3 – 2x at x = 1.

Answer 28

y=x-2

Answer 29

When's your final?

Answer 30

tomorrow! i am sick and stressed and i can't do it!!!

Answer 31

Oh boy.

Answer 32

yea... :(

Answer 33

A differentiable function has the value y(2) = -1 and the derivative value y′(2) = 3. Approximate the value of y(1.9).

Answer 34

Try using multiple questions. Close this one and post again.

It seems the slope of the tangent line is +3 so it's increasing at that point. I think it' be just under -1