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Question

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anonymous · Answer

@douglaswinslowcooper

anonymous · Answer

@Loser66

anonymous · Answer

hi

loser66 · Answer

I m not good at limit. @amistre64

anonymous · Answer

I know how to do limits but I dont get the delta x part

amistre64 · Answer

the change in x,  suppose x = b-a,   x approaches 0 as a approaches b

amistre64 · Answer

jsut consider delta x to be some variable ... h is a usual change

anonymous · Answer

ok I think I see what you are saying so now we have to have 2 equations because there are 2 varibles

amistre64 · Answer

in essense the question is asking:  what is the derivative of sqrt(x-4)

anonymous · Answer

oh how did you get to that im just curious? i have another problem like it to do

amistre64 · Answer

a good approach if you dont know the derivative is to apply the conjugate

anonymous · Answer

I know derivatives and indefinite and definite integral I just learned it and got 100% on my unit test :)

amistre64 · Answer

$$\frac{\sqrt b-\sqrt a}{h}$$
$$\frac{\sqrt b-\sqrt a}{h}\frac{\sqrt b+\sqrt a}{\sqrt b+\sqrt a}$$
$$\frac{b-a}{h(\sqrt b+\sqrt a)}$$

anonymous · Answer

ok so for this one here the answer would be none of the above though correct?

anonymous · Answer

becase the asmptotes are not on -2 it cant go to infinity

amistre64 · Answer

you might want to show me how you approached that conclusion, its not the same one i get

amistre64 · Answer

oh, a different question lol

anonymous · Answer

yes :)

anonymous · Answer

I solved the second one by graphing

amistre64 · Answer

x(x-1)
------
 (x-2)

yeah, its a vertical asymptote since nothing cancels.  The question is, how does it play out as x approached 2 from the negative side?

anonymous · Answer

Ohhhh the calculation is at 2 from the left not -2 silly me

anonymous · Answer

it would be infinity