Question

What is the limiting reactant when 8.4 moles of lithium react with 4.6 moles of oxygen gas?

Unbalanced equation: Li + O2 → Li2O

Show, or explain, all of your work along with the final answer.

Answer 1

@sarah786 do you think you could help me out?

Answer 2

I try .. Can u show me ur work??

Answer 3

umm its simple . :)
Ok first step balance the equation .

Answer 4

it would be Li2O, right?

Answer 5

Actually I've to go in few minutes So I solved it for you .But please try to understand it ,Not just Copy ok :)

Answer 6

Yeah of course! Thanks, you're a life saver. This lesson is really stressing me out, i just need someone to help me really grasp it. I appreciate everything. (:

Answer 7

First balance
4Li + O2 ---> 2Li2O
So it show
4 moles of Li form = 2 moles of LiO2
so
1 -------------= 2/4 moles of LiO2
8.4 -----------= 2/4 x 8.4 moles of LiO2

Answer 8

So for 8.4 moles of Li = 4.2 moles of LiO2

Answer 9

Now same for O2
1 mole of O2 formed = 2 moles of Li2O
So 4.6 mole of O2 formed = 2 x 4.6 = 9.2 mole of Li2O

Answer 10

Because less Li2O is produced from 8.4 mol Li, Li is know as the Limiting reactant. In this situation O2 is in excess.

I hope u got it :)

Answer 11

@official_snowflake

Answer 12

I think i do, i'm going to have to read it a few times though. (: thank you

Answer 13

Yw :)