Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points)

Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points)

Part C: William can only attend a school in his designated zone. William's zone is defined by y

Question

Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points)

Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points)

Part C: William can only attend a school in his designated zone. William's zone is defined by y < -x - 1. Explain how you can identify the schools that William is allowed to attend. (2 points)

anonymous · Answer

help please i already did part b i just dont understand a and c

anonymous · Answer

ill submit the graph

anonymous · Answer

attachment

anonymous · Answer

i just need this last question and im done for winter break thanks for your time

ranga · Answer

Point A is (2, -3)  and  E is (3,1)
The simplest set of inequalities to create would be a line passing through the origin and A   and  another line passing through the origin and E.

anonymous · Answer

thank you do you understand part c

ranga · Answer

C) Plot the line y = -x - 1 and shade the region below that line to represent y < -x -1 and all schools that lie in the shaded area will be the solution.

anonymous · Answer

thankyou so much for you time

ranga · Answer

You are welcome.
For B) when you find the two lines passing thru A and the origin and E and the origin use the inequality y <= ???  for the line OE   and   y >= ???  for the line OA.

anonymous · Answer

ok thanks

ranga · Answer

alright.  Happy Holidays!

ranga · Answer

When you draw the line for part C) draw a dotted line (that is, a non-continuous line because it is a "less than" inequality (<) and not a "less than or equal to" inequality (<=).  So points on the line do NOT belong to the solution set.  When you plot the line I think it will be a 45 degree downward line passing through A and -1 on the y-axis.  Since it is a dotted line and A falls on the line A does not count in the solution.  I think it will leave B and C in the shaded region for the solution set.

For part B, the line should be continuous because we have chosen the points A and E to fall on the line and we should include the points A & E by making the lines continuous and making the inequalities <=  and  >=.