a train 100m long is moving at a speed of 50 km/h crosses a train 120m long coming from opposite direction on parallel tracks in 6 sec. the speed of the second train is
Would love to help, but this question is lacking a question... :/
any method u familiar wid @master71 ?
@techhelper i think we need to find the speed of second train
yes
ah, alright. i think he was still going to give more information. :)
say, speed of second train = \(x\) km/h
relative speed = \(50 + x\) km / h
overlapping distance = 100 + 120 = 220 next, use the relation :- distance = speed x time
can u solve \(x\) ?
no
what is the ans
distance = speed x time \(\frac{220}{1000} = (50+x) \times \frac{6}{60\times 60} \) solve \(x\)
if u want answer, feed it to wolfram http://www.wolframalpha.com/input/?i=%5Cfrac%7B220%7D%7B1000%7D+%3D+%2850%2Bx%29+%5Ctimes+++%5Cfrac%7B6%7D%7B60%5Ctimes+60%7D+
ok thanks
np :)
the ratio of the length and breadth of a plot is 3:2 if the bredth ia 40m less than the length , what is the perimeter of the plot
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